1/5z^2-80+4/z-4=1/z+4

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Solution for 1/5z^2-80+4/z-4=1/z+4 equation: 



1/5z^2-80+4/z-4=1/z+4

We move all terms to the left:

1/5z^2-80+4/z-4-(1/z+4)=0



Domain of the equation: 5z^2!=0

z^2!=0/5

z^2!=√0

z!=0

z∈R





Domain of the equation: z!=0

z∈R





Domain of the equation: z+4)!=0

z∈R



We add all the numbers together, and all the variables

1/5z^2+4/z-(1/z+4)-84=0

We get rid of parentheses

1/5z^2+4/z-1/z-4-84=0

We calculate fractions

We do not support ezpression: z^3

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